Proceed as in Example 4 in Section 11.3 to find a particular solution
xp(t)
of equation (11) in Section 11.3
m
d2x |
dt2 |
+ kx = f(t) (11)
when
m =
1 |
2 |
, k = 16,
and the driving force
f(t)
is as given. Assume that when
f(t)
is extended to the negative t-axis in a periodic manner, the resulting function is even.
f(t) = 2πt − t2,
0 < t < 2π;
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