Question

Show all calculations to support your answers. You may follow the methods shown in the mp4...

Show all calculations to support your answers. You may follow the methods shown in the mp4 on Value of info for a way to answer this question if you wish.

Guide to marks: 20 marks - 4 for (a), 2 for (b), 6 for (c), 2 for (d), 6 for (e)

Round probability calculations to 2 decimal places.

A firm is considering marketing a new product which will be a success or a failure. The prior probability of success is judged to be 0.3.

If the product is marketed and is a success the firm expects to earn $1,000,000, while a failure is expected to lead to a loss of $600,000.

(a) Should the product be marketed? Why?
(b) What is the expected value of perfect information about the success or failure of the product?

The firm is considering a market survey whose results can be classified as favourable or unfavourable. Given past experience with the market survey personnel, the conditional probabilities are p(favourable|success) = 0.7 and p(unfavourable|failure) = 0.8.

(c) Revise the prior probabilities in light of these likely survey results.
(d) What is the posterior probability of success given a favourable survey result?
(e) What is the maximum the firm should pay for the market survey?

Homework Answers

Answer #1

Probability of success =0.3

Probability of failure

Expected earning = 1000000*0.3 - 600000*0.7 = 300000-420000 = -120000

Hence the product shoud not be slated.

b) Expected value = -120000

p(f/s) =0.7 and p(u/F) = 0.8 taking the assumption p(f) =0.5 and p(u) =0.5, p(s) =0.3 and p(F)=0.7

p(s/f) = p(f/s) * p(s)/p(f) = 0.7*0.3 / 0.5 = 0.105

p(s/u) = p(u/s)* p(s)/ p(u) = 0.3*0.3/0.5 = 0.045

Similarly for p(F/f) and p(F/u) will sum upto = 0.8 { use the formula above}

Posterior probability of success given favourable survey results is P(s/f) = 0.105

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