Panamint Systems Corporation is estimating activity costs associated with producing disk drives, tapes drives, and wire drives. The indirect labor can be traced to four separate activity pools. The budgeted activity cost and activity base data by product are provided below.
Activity Cost |
Activity Base |
|||||||||||||||||||
Procurement | $344,300 | Number of purchase orders | ||||||||||||||||||
Scheduling | $239,200 | Number of production orders | ||||||||||||||||||
Materials handling | $436,600 | Number of moves | ||||||||||||||||||
Product development | $761,200 | Number of engineering changes | ||||||||||||||||||
Production | $1,534,300 | Machine hours | ||||||||||||||||||
Number of Purchase Orders |
Number of Production Orders |
Number of Moves |
Number of Engineering Changes |
Machine Hours |
Number of Units |
|||||||||||||||
Disk drives | 4,000 | 380 | 1,340 | 12 | 1,900 | 2,000 | ||||||||||||||
Tape drives | 1,700 | 225 | 790 | 8 | 8,600 | 3,600 | ||||||||||||||
Wire drives | 12,000 | 700 | 3,800 | 20 | 10,700 | 2,200 |
Determine the activity-based cost for each wire drive unit.
A. $251.97
B. $19.45
C. $816.57
D. $305.99
The correct answer is option C.$ 816.57
Procurement cost = (($344300÷(4000+1700+12000))×12000= $233424
Scheduling cost ((239200÷(380+225+700))×700=$128307
Material handling cost.= ((436600÷(1340+790+3800))×3800=$279777
Product development cost= ((761200÷(12+8+20))×20= $380600
Production= ((1534300÷(1900+8600+10700))×10700=774387
Total cost=233424+128307+279777+380600+774387=$1796495
Cost per unit = total cost ÷ total units
$1796495÷2200 units =$ 816.58 which is close to option C. The minor differences is due to round off calculation.
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