Montoure Company uses a periodic inventory system. It entered into the following calendar-year purchases and sales transactions.
Date | Activities | Units Acquired at Cost | Units Sold at Retail | |||||||||
Jan. | 1 | Beginning inventory | 760 | units | @ $70.00 per unit | |||||||
Feb. | 10 | Purchase | 480 | units | @ $67.00 per unit | |||||||
Mar. | 13 | Purchase | 280 | units | @ $52.00 per unit | |||||||
Mar. | 15 | Sales | 880 | units | @ $100.00 per unit | |||||||
Aug. | 21 | Purchase | 260 | units | @ $75.00 per unit | |||||||
Sept. | 5 | Purchase | 660 | units | @ $71.00 per unit | |||||||
Sept. | 10 | Sales | 1,000 | units | @ $100.00 per unit | |||||||
Totals | 2,440 | units | 1,880 | units | ||||||||
Required:
1. Compute cost of goods available for sale and
the number of units available for sale.
2. Compute the number of units in ending inventory.
3. Compute the cost assigned to ending inventory using (a) FIFO, (b) LIFO, (c) weighted average, and (d) specific identification. For specific identification, units sold consist of 760 units from beginning inventory, 220 from the February 10 purchase, 280 from the March 13 purchase, 130 from the August 21 purchase, and 490 from the September 5 purchase.
4. Compute gross profit earned by the company for each of the four costing methods.
1) |
Units available for sale |
Price |
Cost of Goods available |
760 |
70 |
53200 |
|
480 |
67 |
32160 |
|
280 |
52 |
14560 |
|
260 |
75 |
19500 |
|
660 |
71 |
46860 |
|
Total |
2440 |
166280 |
2) Units in ending inventory: Units available - Units sold = 2440-1880 = 560 units |
3) Value of ending inventory: |
a) FIFO = 560*71 = 39760 |
b) LIFO = 560*70 = 39200 |
C) WAM = 560*(166280/2440)=38162.62 |
d) Specific Identification = 166280 - (760*70 + 220*67 + 280*52 + 130*75 + 490*71) = 39240 |
4) Gross Profit = Sales - COGS = Sales - (Cost of goods available - value of ending inventory) |
a) FIFO = (1880*100) - (166280-39760) = 61480 |
b) LIFO = (1880*100) - (166280-39200) = 60920 |
c) WAM = (1880*100) - (166280-38162.62) = 59882.62 |
d) Specific Identification = (1880*100) - (166280-39240) = 60960 |
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