Question

A 200-mm-long aluminum tube, closed at its ends, is 100 mm in diameter

with a wall thickness of 2 mm. If the tube just fits between two rigid walls at

zero internal pressure, determine the longitudinal and tangential stresses at an 2192

internal pressure of 4 MN/m . Assume υ = 3 and E = 70 X 10 N/m .

Answer 1

Given data follows below:

Long aluminum tube =200-mm

Diameter closed at its ends =100 mm

Wall thickness of = 2 mm

Internal pressure of = 4 MN/m

U = 3 and

E = 70 X 10 N/m .

Now calculating longitudinal stresses

pd/4t = (4x10⁶ N/m²)(100x10^-3m) / 4x2x10^-3m

= 0.5 x 10⁸ N/m^2

= 50 MPa

Now calculating tangential stresses at an 2192

pd/2t = (4x10⁶ N/m²)(100x10^-3m) / 2x2x10^-3m

= 10⁸ N/m^2

= 100 MPa

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