Question

If the average arrival rate is 10 per hour, and the average time it takes to...

If the average arrival rate is 10 per hour, and the average time it takes to help a customer is 5 minutes, then:

Group of answer choices

No customer will ever have to wait: we can help more customers per hour than arrive

Utilization is less than 100%: we can help more customers per hour than arrive, but we may have a queue form and customers might have to wait..

None of the other answers are correct

There can never be queue: we can help more customers per hour than arrive

Homework Answers

Answer #1

Assuming M/M/1 Queuing Model

Average arrival rate = 10/hr

Average Service rate = 1 per minutes = 20/hr

Server Utilization = 10/20 = 0.5 = 50%

Which means system is stable

Probability of 1 customer in system is P1= = 0.5 x 0.5 = 0.25

Probability more than 1 customer in queue = 1-P1 = 1-0.25 = 0.75

Now let us look at options

Option 1: As there is a probability of 0.75, that there can be 2 or more customers in queue. Customer may have to wait, hence option 1 is false.

Option 2: Yes, utilzation is less than 100% we got 50% and we can help more customers per hour than current situation but they may have to wait which is also true. Hence, over all we can conclude that this statement is Correct.

Remaining options are also incorrect

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
With an average service rate of 15 customers per hour and an average customer arrival rate...
With an average service rate of 15 customers per hour and an average customer arrival rate of 12 customers per hour, calculate the probability that actual service time will be less than or equal to five minutes.
Arrival Rate = 1/50 = 0.02 calls hour. Service Rate= 1 hour (travel time) + 1.5...
Arrival Rate = 1/50 = 0.02 calls hour. Service Rate= 1 hour (travel time) + 1.5 hour (repair time) =2.5 hours With m = 1/ 2.5 = 0.4 hours per customers ** PLEASE SHOW HOW TO DO EQUATION ** OEI is satisfied that one service technician can handle the 10 existing customers. Use a waiting line model to determine the following information: (a) probability that no customers are in the system, (b) average number of customers in the waiting line,...
For an M/M/1/GD/∞/∞ queuing system with arrival rate λ = 16 customers per hour and service...
For an M/M/1/GD/∞/∞ queuing system with arrival rate λ = 16 customers per hour and service rate μ = 20 customers per hour, on the average, how long (in minutes) does a customer wait in line (round off to 3 decimal digits)?
A simple queueing system has an arrival rate of 6 per hour and a service rate...
A simple queueing system has an arrival rate of 6 per hour and a service rate of 10 per hour. For this system the average time in line has been estimated to be 20 minutes. Using Little’s Law estimate the following: Average time in the queueing system Average number of customers in the queueing system Average number of customers in the queue Average number of customers in service.
In a car pressure wash the average arrival rate is 12 cars per hour and are...
In a car pressure wash the average arrival rate is 12 cars per hour and are serviced at an average rate of 15 cars per hour, with service times exponential. It is requested: a) Probability that the system is empty. b) Average number of clients in the washing system. c) Average number of clients in the row. d) Average time a customer waits in line. e) Probability of having a row of more than 2 clients. f) Probability of waiting...
Scenario: There is only one teller working at a bank. The teller takes an average of...
Scenario: There is only one teller working at a bank. The teller takes an average of 3 minutes to service a customer. Assume that the time the teller takes to service a customer can be represented as an Exponential Probability distribution. Customers arrive at the teller line at the average rate of 1every 10 minutes. Their arrival pattern follows a Poisson distribution. Of 200 customers who get serviced by the teller, how many can expect to be serviced in more...
Visitors arrive at Kid’s World entertainment park according to an exponential inter-arrival time distribution with mean...
Visitors arrive at Kid’s World entertainment park according to an exponential inter-arrival time distribution with mean 2.5 minutes. The travel time from the entrance to the ticket window is normally distributed with a mean of 3 minutes and a standard deviation of 0.5 minute. At the ticket window, visitors wait in a single line until one of four cashiers is available to serve them. The time for the purchase of tickets is normally distributed with a mean of five minutes...
An automatic roller coaster ride takes a constant time of 2.5 minutes to complete a ride....
An automatic roller coaster ride takes a constant time of 2.5 minutes to complete a ride. Customers arrive at the facility every 2.75 minutes (exponentially distributed). Report answers to 4 decimal places. a. Determine the average waiting time in the queue (in minutes). b. The local bank drive-through teller window can serve a customer at an average of 4.5 minutes per customer (exponentially distributed). Customers arrive in their cars at a rate of 12 per hour (poisson distributed). Determine the...
Benny the Barber gives a haircut in an average of 8 minutes. HIs market survey data...
Benny the Barber gives a haircut in an average of 8 minutes. HIs market survey data indicates that customers arrive at a rate of 4 per hour. Benny knows that customers exhibit a Poisson arrival distribution and that he provides an exponential service distribution. (Round intermediate calculations to 3 decimals & final answers to 2 decimals) [a] What is the average number of customers waiting? [b] What is the average wait time, per customer? [c] What is the average time...
Suppose that customers arrive to a ATM in a POisson arrival with 3 person/hour. Assume that...
Suppose that customers arrive to a ATM in a POisson arrival with 3 person/hour. Assume that it takes on average 5 minutes with variance = 4 for the ATM to process each transaction. Answer the following questions a. On average how many people are waiting in the line? b. On average how much time will people need to wait in line? Suppose there are two identical ATM machines. Answer (a) and (b) for Q2.