Let no. of units produced for product L be x and for product V be y.
Therefore, one unit of x needs 5 labour hours and 2 machine hours.
Similarly one unit of y needs 4 labour hours and 8 machine hours.
Hence following linear programming equation will be formed
EQUATION 1 5x + 4y = 80,000
and
EQUATION 2 2x + 8y = 60,000
Solving the second equation, 8y = 60,000-2x
4y= 30,000-x, now putting this value in eq 1
5x + 30,000 - x = 80,000
4x=50,000
we get,
x= 12,500 units
Hence, 12,500 units will be produced of L for maximum profit.
hope you got the answer, please comment for any clarification
Thankyou and all the best for future
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