a) If Sultan takes a loan, Cost of construction = RO 50,000
Loan amount (P)= RO 50,000
Interest charged monthly(R) = 8/12 = 1.5%
No of monthly installments(n) = 12 x 6 = 72
Monthly payment = [P x R x (1 + R )^n / [(1 + R)^n - 1 ]
= [50000 x 0.015 x (1+0.015)^72] / [(1 + 0.015 )^72 - 1]
= RO 1,140.39
Therefore, the amount to be paid in option A = 1140.39 x 72 = RO 82,108
B) If Sultan saves RO 900 every month
PMT = RO 900
n = 72
R = 6 / 12 = 0.5%
FV = PMT x [(1 + R)^n - 1] / r
FV = 900 x [(1 + 0.005)^72 - 1] / 0.005
FV = 77767.97 = RO 77,768
So the amount saved in 6 years by saving RO 900 per month at 6% per annum is equal to RO 77,768
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