Question

A small regional carrier accepted 15 reservations for a particular flight with 11 seats. 7 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 43% chance, independently of each other.
Find the probability that overbooking occurs.    
Find the probability that the flight has empty seats.    

Answer 1

ANSWER

Probability that overbooking occurs = Probability that the extra passengers all 5 of them arrive

= 0.43*0.43*.... 8 times

= 0.43⁸

= 0.0011688

0.0011688 is the probability that overbooking occurs.

b) Probability that the flight has extra seats

= 1 - Probability that 11 or 15 passengers arrive

= 1 - 0.0011688 - 8*0.0011688

= 0.9895

0.9895 is the required probability here.

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